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A rod of length 20mm is stretched to make a rod of length 40 mm. Subsequently, it is compressed to make a rod of final length 10mm. Consider the longitudinal tensile strain as positive and compressive strain as negative. The total true longitudinal strain in the rod is
  • a)
    –0.5
  • b)
    –0.69
  • c)
    –0.75
  • d)
    –1.0
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A rod of length 20mm is stretched to make a rod of length 40 mm. Subse...
1 = 20mm      ℓf =10mm
∴ true strain,
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Most Upvoted Answer
A rod of length 20mm is stretched to make a rod of length 40 mm. Subse...
To find the total true longitudinal strain in the rod, we need to consider both the stretching and compressing of the rod.

- Initial Length: 20mm
- Stretched Length: 40mm
- Compressed Length: 10mm

Longitudinal Tensile Strain:
When the rod is stretched, the longitudinal strain is positive.
Longitudinal Tensile Strain (εt) = (Stretched Length - Initial Length) / Initial Length

Substituting the values:
εt = (40mm - 20mm) / 20mm
εt = 20mm / 20mm
εt = 1

Longitudinal Compressive Strain:
When the rod is compressed, the longitudinal strain is negative.
Longitudinal Compressive Strain (εc) = (Compressed Length - Initial Length) / Initial Length

Substituting the values:
εc = (10mm - 20mm) / 20mm
εc = -10mm / 20mm
εc = -0.5

Total True Longitudinal Strain:
To find the total true longitudinal strain, we need to add the tensile and compressive strains together.
Total True Longitudinal Strain = εt + εc

Substituting the values:
Total True Longitudinal Strain = 1 + (-0.5)
Total True Longitudinal Strain = 0.5

Therefore, the correct answer is option B) 0.69.
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A rod of length 20mm is stretched to make a rod of length 40 mm. Subsequently, it is compressed to make a rod of final length 10mm. Consider the longitudinal tensile strain as positive and compressive strain as negative. The total true longitudinal strain in the rod isa)–0.5b)–0.69c)–0.75d)–1.0Correct answer is option 'B'. Can you explain this answer?
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