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A lamp rated at 60V, 40W is to be connected across 230V. What is the value of resistance to be connected in series with lamp?
- a)100Ω
- b)255Ω
- c)90Ω
- d)345Ω
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A lamp rated at 60V, 40W is to be connected across 230V. What is the v...
Rating of lamp = 60V, 40 W
When lamp is connected, maximum current that can be flow through the circuit is
Let RS be the series resistance.
Most Upvoted Answer
A lamp rated at 60V, 40W is to be connected across 230V. What is the v...
To find the value of resistance to be connected in series with the lamp, we can use Ohm's Law.
Ohm's Law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.
First, let's find the current passing through the lamp without any additional resistance.
Using the power formula: P = IV
40W = 60V * I
Solving for I:
I = 40W / 60V
I ≈ 0.67A
Now, let's find the resistance needed to be connected in series with the lamp.
Using Ohm's Law: V = IR
We want to find the resistance, so let's rearrange the formula:
R = V / I
Substituting the given values:
R = 230V / 0.67A
R ≈ 343.28Ω
Therefore, the value of resistance to be connected in series with the lamp is approximately 343.28Ω.
Ohm's Law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.
First, let's find the current passing through the lamp without any additional resistance.
Using the power formula: P = IV
40W = 60V * I
Solving for I:
I = 40W / 60V
I ≈ 0.67A
Now, let's find the resistance needed to be connected in series with the lamp.
Using Ohm's Law: V = IR
We want to find the resistance, so let's rearrange the formula:
R = V / I
Substituting the given values:
R = 230V / 0.67A
R ≈ 343.28Ω
Therefore, the value of resistance to be connected in series with the lamp is approximately 343.28Ω.
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