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The drift velocity is 5V and the applied electric field intensity 20v/m what will be the mobility of charge carriers.
  • a)
    100 m2/ (vs)
  • b)
     4 m2/ (vs)
  • c)
    15 m2/ (vs)
  • d)
    0.25 m2/ (vs)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The drift velocity is 5V and the applied electric field intensity 20v/...
We know that mobility of charge carriers is drift velocity divide by applied electric field intensity. Mobility = drift velocity / field intensity.
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Most Upvoted Answer
The drift velocity is 5V and the applied electric field intensity 20v/...
Given:
- Drift velocity (vd) = 5V
- Electric field intensity (E) = 20V/m

To find: Mobility (μ) of charge carriers

Formula:
Mobility (μ) = Drift velocity (vd) / Electric field intensity (E)

Calculation:
Substitute the given values in the formula,
μ = vd / E
μ = 5V / 20V/m
μ = 0.25 m²/(V.s)

Therefore, the mobility of charge carriers is 0.25 m²/(V.s), which is option D.

Explanation:
- Drift velocity is the velocity with which free electrons move in a conductor when an electric field is applied.
- Electric field intensity is the strength of the electric field at a particular point in space.
- Mobility is a measure of how easily charge carriers can move through a material under the influence of an electric field.
- The formula for mobility relates the drift velocity and electric field intensity.
- In this case, the drift velocity is 5V and the electric field intensity is 20V/m.
- Substituting these values in the formula gives the mobility as 0.25 m²/(V.s).
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The drift velocity is 5V and the applied electric field intensity 20v/m what will be the mobility of charge carriers.a)100 m2/ (vs)b)4 m2/ (vs)c)15 m2/ (vs)d)0.25 m2/ (vs)Correct answer is option 'D'. Can you explain this answer?
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