Directions: The answer to the following question is a single digit int...
Molecular formula of N-methyl butanamine is C5H13N. Primary, secondary and tertiary amines are different functional groups and metamerism cannot coexist with functional isomerism. Hence, we shall consider only those isomers of N-methyl butanamine which are secondary (2o) amines.
Every molecule of group A is a meramer of every molecule in group B
View all questions of this test
Directions: The answer to the following question is a single digit int...
Explanation:
To find the number of open chain structures or metamers possible for N-Methly butanamine, we need to understand the concept of metamers and analyze the molecule.
Metamers:
Metamers are constitutional isomers that have the same molecular formula but differ in the location of the functional group or the alkyl group on the carbon chain. In other words, metamers have different arrangements of the alkyl groups attached to the functional group.
N-Methly butanamine:
N-Methly butanamine is an amine compound with the molecular formula C5H13N. The general structure of the compound is as follows:
CH3-CH2-CH2-CH2-NH-CH3
Analysis:
In the given structure, the functional group is the amine group (-NH2) located at the end of the carbon chain. To determine the number of metamers, we need to consider the different arrangements of the alkyl groups (methyl groups -CH3) attached to the nitrogen atom.
Number of Methyl Groups:
In N-Methly butanamine, there are two methyl groups (CH3) attached to the nitrogen atom.
Possible Arrangements:
To find the possible arrangements, we can consider the two methyl groups as distinct entities (M1 and M2) and analyze the different ways they can be arranged on the nitrogen atom.
Possible Arrangements:
1. M1 on the left and M2 on the right of the nitrogen atom: CH3-NH-CH3
2. M1 on the right and M2 on the left of the nitrogen atom: CH3-NH-CH3
3. M1 and M2 both on the left of the nitrogen atom: CH3-CH3-NH
4. M1 and M2 both on the right of the nitrogen atom: NH-CH3-CH3
5. M1 on the left and M2 on the right of the nitrogen atom, but attached to different carbon atoms: CH3-NH-CH3
6. M1 on the right and M2 on the left of the nitrogen atom, but attached to different carbon atoms: CH3-NH-CH3
Conclusion:
From the above analysis, we can see that there are a total of 6 possible arrangements of methyl groups (metamers) for N-Methly butanamine. Therefore, the correct answer is '6'.
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.