How many three-digit numbers can be formed with the digits 3, 0 and 7 ...
The three-digit numbers that can be formed with the digits 3, 0 and 7 can be listed as 307, 370, 703, 730.
Thus, 4 three-digit numbers can be formed with the given digits without repetition.
Hence, the correct answer is C.
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How many three-digit numbers can be formed with the digits 3, 0 and 7 ...
To solve this problem, we can use the fundamental counting principle and consider each digit separately.
We have three digits to choose from: 3, 0, and 7. Since repetition is not allowed, we can use each digit only once in each three-digit number.
Step 1: Choose the hundreds digit
Since we need a three-digit number, the hundreds digit cannot be 0. Therefore, we have two choices for the hundreds digit: 3 or 7.
Step 2: Choose the tens digit
After choosing the hundreds digit, we have two digits remaining: 0 and the remaining digit from step 1. We can choose any of these two digits as the tens digit.
Step 3: Choose the units digit
After choosing the hundreds and tens digits, we have one digit remaining: the remaining digit from step 2. Therefore, we have only one choice for the units digit.
Step 4: Count the total number of possibilities
To find the total number of three-digit numbers, we multiply the number of choices for each digit: 2 choices for the hundreds digit, 2 choices for the tens digit, and 1 choice for the units digit.
Total number of possibilities = 2 x 2 x 1 = 4
Therefore, there are 4 three-digit numbers that can be formed using the digits 3, 0, and 7 without repetition. Hence, option C is the correct answer.
How many three-digit numbers can be formed with the digits 3, 0 and 7 ...
The correct answer is C - Explanation - The three-digit numbers that can be formed with the digits 3, 0, and 7 can be listed as 307, 370, 703, 730.
Thus, 4 three-digit numbers can be formed with the given digits without repetition.
Hence, the correct answer is C. I hope you understand now
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