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Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.
Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2 at STP is produced. The molar ratio of ethane and propane in the mixture is
Correct answer is '2'. Can you explain this answer?
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Combustion of Ethane and Propane
When ethane (C2H6) and propane (C3H8) undergo complete combustion, they react with oxygen to produce carbon dioxide (CO2) and water (H2O). The balanced chemical equations for these reactions are:
- Ethane: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
- Propane: C3H8 + 5 O2 → 3 CO2 + 4 H2O
Calculating CO2 Production
From the equations:
- 2 volumes of ethane produce 4 volumes of CO2.
- 1 volume of propane produces 3 volumes of CO2.
This means that:
- 1 volume of ethane produces 2 volumes of CO2 (4 CO2 / 2 C2H6).
- 1 volume of propane produces 3 volumes of CO2.
Volume Contribution to CO2
Let the volume of ethane in the mixture be 'x' L and the volume of propane be 'y' L. The total volume of the mixture is given as:
- x + y = 9 L
The CO2 produced from the combustion of ethane and propane can be expressed as:
- CO2 from ethane = 2x L
- CO2 from propane = 3y L
The total CO2 produced is 21 L:
- 2x + 3y = 21 L
Solving the Equations
Now we have a system of equations:
1. x + y = 9
2. 2x + 3y = 21
By solving these equations, we can determine the values of 'x' and 'y'.
From the first equation, we can express y in terms of x:
- y = 9 - x
Substituting this into the second equation:
- 2x + 3(9 - x) = 21
- 2x + 27 - 3x = 21
- -x + 27 = 21
- x = 6 (ethane)
Substituting back to find y:
- y = 9 - 6 = 3 (propane)
Molar Ratio
The molar ratio of ethane to propane is:
- x : y = 6 : 3 = 2 : 1
Thus, the correct answer regarding the molar ratio of ethane to propane in the mixture is '2'.
When ethane (C2H6) and propane (C3H8) undergo complete combustion, they react with oxygen to produce carbon dioxide (CO2) and water (H2O). The balanced chemical equations for these reactions are:
- Ethane: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
- Propane: C3H8 + 5 O2 → 3 CO2 + 4 H2O
Calculating CO2 Production
From the equations:
- 2 volumes of ethane produce 4 volumes of CO2.
- 1 volume of propane produces 3 volumes of CO2.
This means that:
- 1 volume of ethane produces 2 volumes of CO2 (4 CO2 / 2 C2H6).
- 1 volume of propane produces 3 volumes of CO2.
Volume Contribution to CO2
Let the volume of ethane in the mixture be 'x' L and the volume of propane be 'y' L. The total volume of the mixture is given as:
- x + y = 9 L
The CO2 produced from the combustion of ethane and propane can be expressed as:
- CO2 from ethane = 2x L
- CO2 from propane = 3y L
The total CO2 produced is 21 L:
- 2x + 3y = 21 L
Solving the Equations
Now we have a system of equations:
1. x + y = 9
2. 2x + 3y = 21
By solving these equations, we can determine the values of 'x' and 'y'.
From the first equation, we can express y in terms of x:
- y = 9 - x
Substituting this into the second equation:
- 2x + 3(9 - x) = 21
- 2x + 27 - 3x = 21
- -x + 27 = 21
- x = 6 (ethane)
Substituting back to find y:
- y = 9 - 6 = 3 (propane)
Molar Ratio
The molar ratio of ethane to propane is:
- x : y = 6 : 3 = 2 : 1
Thus, the correct answer regarding the molar ratio of ethane to propane in the mixture is '2'.
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Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2at STP is produced. The molar ratio of ethane and propane in the mixture isCorrect answer is '2'. Can you explain this answer?
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Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2at STP is produced. The molar ratio of ethane and propane in the mixture isCorrect answer is '2'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2at STP is produced. The molar ratio of ethane and propane in the mixture isCorrect answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2at STP is produced. The molar ratio of ethane and propane in the mixture isCorrect answer is '2'. Can you explain this answer?.
Solutions for Directions: The answer to the following question is a single digit integer ranging from 0 to 9. Enter the correct digit in the box given below.Q. On complete combustion of a 9 L mixture of ethane and propane, 21 L of CO2at STP is produced. The molar ratio of ethane and propane in the mixture isCorrect answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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