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The solubility of urea in methanol is 17 g urea/100 mL methanol. Density of methanol is 0.792 g/mL at 293 K at which vapour pressure of methanol is 96.0 mm of Hg. Thus, vapour pressure of saturated solution of urea in methanol is 
  • a)
    86.11 mm hg
  • b)
    90.27 mm hg
  • c)
    88.13 mm hg
  • d)
    80.12 mm hg
Correct answer is option 'A'. Can you explain this answer?
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Solubility of Urea in Methanol

The solubility of urea in methanol is given as 17 g urea/100 mL methanol. This means that 100 mL of methanol can dissolve 17 g of urea at the given conditions.

Density of Methanol

The density of methanol is given as 0.792 g/mL at 293 K. This means that 1 mL of methanol weighs 0.792 g at this temperature.

Vapour Pressure of Methanol

The vapour pressure of methanol is given as 96.0 mm of Hg at 293 K. This means that at this temperature, the pressure exerted by the vapour of methanol is 96.0 mm Hg.

Vapour Pressure of Saturated Solution

To determine the vapour pressure of the saturated solution of urea in methanol, we need to consider the effect of the solute (urea) on the vapour pressure of the solvent (methanol).

When a solute is dissolved in a solvent, the vapour pressure of the solvent decreases. This is known as the Raoult's law. According to Raoult's law, the vapour pressure of a solvent above a solution is equal to the mole fraction of the solvent multiplied by its vapour pressure in the pure state.

Calculating Mole Fraction

To calculate the mole fraction of methanol in the saturated solution, we need to determine the moles of methanol and urea present in the solution.

Since the density of methanol is given as 0.792 g/mL, we can calculate the volume of methanol required to dissolve 17 g of urea.

17 g urea * (100 mL methanol/17 g urea) = 100 mL methanol

Therefore, the volume of methanol required to dissolve 17 g of urea is 100 mL.

Next, we need to calculate the moles of methanol and urea.

Moles of methanol = Volume of methanol (in liters) * Density of methanol (in g/mL) / Molar mass of methanol

Moles of methanol = 100 mL * (1 L/1000 mL) * 0.792 g/mL / 32.04 g/mol = 0.0246 mol

Moles of urea = Mass of urea / Molar mass of urea = 17 g / 60.06 g/mol = 0.283 mol

Calculating Mole Fraction of Methanol

Mole fraction of methanol = Moles of methanol / Total moles in solution

Mole fraction of methanol = 0.0246 mol / (0.0246 mol + 0.283 mol) = 0.0803

Calculating Vapour Pressure of Saturated Solution

According to Raoult's law, the vapour pressure of methanol in the saturated solution is equal to the mole fraction of methanol multiplied by its vapour pressure in the pure state.

Vapour pressure of saturated solution = Mole fraction of methanol * Vapour pressure of methanol

Vapour pressure of saturated solution = 0.0803 * 96.0 mm Hg = 7
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The solubility of urea in methanol is 17 g urea/100 mL methanol. Density of methanol is 0.792 g/mL at 293 K at which vapour pressure of methanol is 96.0 mm of Hg. Thus, vapour pressure of saturated solution of urea in methanol isa)86.11 mm hgb)90.27 mm hgc)88.13 mm hgd)80.12 mm hgCorrect answer is option 'A'. Can you explain this answer?
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The solubility of urea in methanol is 17 g urea/100 mL methanol. Density of methanol is 0.792 g/mL at 293 K at which vapour pressure of methanol is 96.0 mm of Hg. Thus, vapour pressure of saturated solution of urea in methanol isa)86.11 mm hgb)90.27 mm hgc)88.13 mm hgd)80.12 mm hgCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The solubility of urea in methanol is 17 g urea/100 mL methanol. Density of methanol is 0.792 g/mL at 293 K at which vapour pressure of methanol is 96.0 mm of Hg. Thus, vapour pressure of saturated solution of urea in methanol isa)86.11 mm hgb)90.27 mm hgc)88.13 mm hgd)80.12 mm hgCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The solubility of urea in methanol is 17 g urea/100 mL methanol. Density of methanol is 0.792 g/mL at 293 K at which vapour pressure of methanol is 96.0 mm of Hg. Thus, vapour pressure of saturated solution of urea in methanol isa)86.11 mm hgb)90.27 mm hgc)88.13 mm hgd)80.12 mm hgCorrect answer is option 'A'. Can you explain this answer?.
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