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Which of the following liquid pairs shows a positive deviation from Raoult’s law?
  • a)
    water+HCl
  • b)
    benzene+methanol
  • c)
    water+nitriic acid
  • d)
    acetone+chloroform
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Which of the following liquid pairs shows a positive deviation from Ra...
 (b)
(a) When HCI is mixed with H20, force of attraction between HCI and H2O  molecules is increased (due to dissolution), hence vaporisation decreased, a case of negative deviation.
(b) CH3OH molecules are joined by intermolecular H-bonding which provides it a liquid state. On adding benzene, H-bonding breaks and force of attraction between CH3OH and benzene molecules is less than between CH3OH-CH3OH and between benzene-benzene hence, more vaporisation of mixture, a case of positive deviation.
(c) As in (a), negative deviation.
(d) CH3COCH3 and CHCI3 are volatile. On mixing, there is increase in intermolecular H-bonding due to the formation of chloretone (A)
Thus, force of attraction between (CHCI3-CH3OCH3) molecules is larger than between (CHCI3-CHCI3)and (CH3COCH3 - CH3OC H3) molecules. Thus, vaporisation decreases, a case of negative deviation.
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Most Upvoted Answer
Which of the following liquid pairs shows a positive deviation from Ra...
Positive deviation from Raoult's Law in Benzene-Methanol Liquid Pair

Raoult's law states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent in the solution. However, some liquid pairs show positive deviations from Raoult's law, which means that the vapor pressure of the solution is higher than what is predicted by Raoult's law. One such liquid pair is benzene-methanol.

Reasons for Positive Deviation

The positive deviation from Raoult's law in benzene-methanol can be attributed to the following reasons:

1. Intermolecular Forces: The intermolecular forces between benzene and methanol molecules are not similar. The benzene molecule has weak London dispersion forces, while the methanol molecule has strong hydrogen bonding. This mismatch in intermolecular forces leads to a positive deviation from Raoult's law.

2. Molecular Size: The molecular size of benzene and methanol is also different. Benzene is a larger molecule than methanol. Due to this difference in size, the benzene molecules cannot pack as closely with the methanol molecules, leading to a positive deviation from Raoult's law.

Implications of Positive Deviation

The positive deviation from Raoult's law in benzene-methanol has important implications in the chemical industry. For example, distillation processes that rely on Raoult's law to separate components will not work as expected in this liquid pair. The positive deviation also affects the boiling point and freezing point of the solution, making it difficult to predict these properties accurately.

Conclusion

The benzene-methanol liquid pair shows a positive deviation from Raoult's law due to differences in intermolecular forces and molecular size. This deviation has important implications in the chemical industry and affects the properties of the solution.
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Which of the following liquid pairs shows a positive deviation from Raoult’s law?a)water+HClb)benzene+methanolc)water+nitriic acidd)acetone+chloroformCorrect answer is option 'B'. Can you explain this answer?
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