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A full – adder can be implemented with half – adders and OR gates. A 4 – bit parallel full adder without any initial carry requires
  • a)
    8 half – adders, 5 – OR gates
  • b)
    8 half – adders, 4 – OR gates
  • c)
    7 half – adders, 4 – OR gates
  • d)
    7 half – adders, 3 – OR gates
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A full – adder can be implemented with half – adders and O...
A full adder can be implemented with 2 half adders and one OR gate.
A 4-bit parallel adder can be implemented using 3 full adders and one half adder.
Hence we require 7 half adders and 3 OR gates to implement 4-bit parallel adder.
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A full – adder can be implemented with half – adders and O...
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A full – adder can be implemented with half – adders and OR gates. A 4 – bit parallel full adder without any initial carry requiresa)8 half – adders, 5 – OR gatesb)8 half – adders, 4 – OR gatesc)7 half – adders, 4 – OR gatesd)7 half – adders, 3 – OR gatesCorrect answer is option 'D'. Can you explain this answer?
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A full – adder can be implemented with half – adders and OR gates. A 4 – bit parallel full adder without any initial carry requiresa)8 half – adders, 5 – OR gatesb)8 half – adders, 4 – OR gatesc)7 half – adders, 4 – OR gatesd)7 half – adders, 3 – OR gatesCorrect answer is option 'D'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A full – adder can be implemented with half – adders and OR gates. A 4 – bit parallel full adder without any initial carry requiresa)8 half – adders, 5 – OR gatesb)8 half – adders, 4 – OR gatesc)7 half – adders, 4 – OR gatesd)7 half – adders, 3 – OR gatesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A full – adder can be implemented with half – adders and OR gates. A 4 – bit parallel full adder without any initial carry requiresa)8 half – adders, 5 – OR gatesb)8 half – adders, 4 – OR gatesc)7 half – adders, 4 – OR gatesd)7 half – adders, 3 – OR gatesCorrect answer is option 'D'. Can you explain this answer?.
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