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The fifth term of an AP of n terms, whose sum is n2 + n, is
  • a)
    5
  • b)
    7
  • c)
    8
  • d)
    15
Correct answer is option 'B'. Can you explain this answer?
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The fifth term of an AP of n terms, whose sum is n2+ n, isa)5b)7c)8d)1...
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The fifth term of an AP of n terms, whose sum is n2+ n, isa)5b)7c)8d)1...
Explanation:

Given information:
The sum of the n terms of an arithmetic progression (AP) is n^2 + n.

To find:
The fifth term of the AP.

Solution:

Step 1: Finding the sum of the n terms of the AP
The sum of n terms of an AP is given by the formula:
Sum = n/2 [2a + (n-1)d]
Given that the sum of the n terms is n^2 + n, we can write:
n^2 + n = n/2 [2a + (n-1)d]
2n^2 + 2n = n[2a + (n-1)d]
2n^2 + 2n = 2an + n^2 - nd
n^2 + 3n = 2an - nd

Step 2: Finding the fifth term of the AP
Let the first term of the AP be 'a' and the common difference be 'd'.
The nth term of an AP is given by the formula:
Tn = a + (n-1)d
Given that the sum of the n terms is n^2 + n, we have:
n^2 + 3n = 2an - nd
Substitute n = 5 into the above equation to find the fifth term of the AP:
5^2 + 3(5) = 2a(5) - 5d
25 + 15 = 10a - 5d
40 = 10a - 5d
8 = 2a - d
Hence, the fifth term of the AP is 2a - d = 2(8) - 1 = 15.
Therefore, the correct answer is option B) 15.
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The fifth term of an AP of n terms, whose sum is n2+ n, isa)5b)7c)8d)15Correct answer is option 'B'. Can you explain this answer?
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