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To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas?
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To raise the temperature of one mole of a gas at constant at constant ...
Identification of Gas
To identify the gas, we need to calculate its molar specific heat at constant volume.
Calculating molar specific heat at constant volume
From the given information, we know that,
ΔT = 10°C = 10 K (change in temperature)
q = 498.6 J (heat energy)
n = 1 mol (number of moles)
Using the formula,
q = nCvΔT
We can calculate the molar specific heat at constant volume (Cv) as,
Cv = q / nΔT
Cv = (498.6 J) / (1 mol * 10 K)
Cv = 49.86 J/mol K
Comparing with Gas Constants
Now, we can compare this value of Cv with the known gas constants for different gases, such as,
- Monoatomic ideal gas: Cv = (3/2)R = 12.47 J/mol K
- Diatomic ideal gas: Cv = (5/2)R = 20.79 J/mol K
- Triatomic ideal gas: Cv = (6/2)R = 24.94 J/mol K
Since the calculated value of Cv (49.86 J/mol K) is closer to the value for a monoatomic ideal gas, we can conclude that the gas is most likely a monoatomic ideal gas.
Therefore, the gas can be Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), or Radon (Rn).
Conclusion
Based on the given information, we can conclude that the gas is most likely a monoatomic ideal gas and it can be Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), or Radon (Rn).
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To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas?
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To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas?.
To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To raise the temperature of one mole of a gas at constant at constant volume from 600 degree celsius to 610 degree celsius, the heat needed is 498.6 j. Which is the gas?.
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