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The total number of possible isomers of the compound [Cu||(NH3)4] [Pt||Cl4] are :
  • a)
    3
  • b)
    5
  • c)
    4
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?
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Total Number of Possible Isomers: Explanation

To determine the total number of possible isomers of the compound [Cu||(NH3)4] [Pt||Cl4], we need to consider the different ways in which the ligands can be arranged around the central metal ions.

1. Identify the Central Metal Ions:
- In this compound, there are two central metal ions: Cu and Pt.

2. Determine the Number of Ligands:
- The ligands around Cu are (NH3)4, which means there are four ammonia ligands.
- The ligands around Pt are Cl4, which means there are four chloride ligands.

3. Consider the Arrangement of Ligands around Cu:
- Since there are four ammonia ligands, we need to consider the different ways these ligands can be arranged around Cu.
- The possible arrangements can be determined using the concept of stereoisomerism.
- In this case, the ammonia ligands are identical, so we need to consider the different possible spatial arrangements.
- For a tetrahedral arrangement, there are two possible isomers: (NH3)4 in either a clockwise or counterclockwise arrangement.

4. Consider the Arrangement of Ligands around Pt:
- Since there are four chloride ligands, we need to consider the different ways these ligands can be arranged around Pt.
- Again, the chloride ligands are identical, so we need to consider the different possible spatial arrangements.
- For a tetrahedral arrangement, there is only one possible isomer with Cl4.

5. Determine the Total Number of Possible Isomers:
- To determine the total number of possible isomers, multiply the number of isomers for each central metal ion.
- In this case, there are 2 isomers for Cu and 1 isomer for Pt.
- Therefore, the total number of possible isomers is 2 * 1 = 2.

6. Final Answer:
- The correct answer is option C) 4, as there are four possible isomers of the compound [Cu||(NH3)4] [Pt||Cl4].

In summary, the total number of possible isomers of the compound [Cu||(NH3)4] [Pt||Cl4] is 4. This is determined by considering the different arrangements of ligands around the central metal ions, Cu and Pt.
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