Calculation of Number of Litres of N/10 Solution

To calculate the number of litres of N/10 solution that can be prepared from 63gm of oxalic acid, we need to follow the steps mentioned below:

Step 1: Calculate the molecular weight of oxalic acid.
The molecular weight of oxalic acid is calculated as follows:
C (2 atoms) = 2 x 12.01 = 24.02
H (2 atoms) = 2 x 1.01 = 2.02
O (4 atoms) = 4 x 16.00 = 64.00
Molecular Weight of Oxalic Acid = 24.02 + 2.02 + 64.00 = 90.04

Step 2: Calculate the number of moles of Oxalic acid.
Number of moles of oxalic acid is calculated as follows:
Number of moles = weight of oxalic acid / molecular weight of oxalic acid
Number of moles = 63 / 90.04 = 0.699 mol

Step 3: Calculate the volume of N/10 solution.
The volume of N/10 solution is calculated as follows:
1 litre of N/10 solution contains 1/10th of a mole of the solute.
Number of moles of solute = 1/10th of a mole
Number of moles of the solute = 0.699 / 10 = 0.0699 mol

Volume of N/10 solution = Number of moles of solute / Normality
Volume of N/10 solution = 0.0699 / 0.1 = 0.699 L

Therefore, 0.699 litres of N/10 solution can be prepared from 63gm of oxalic acid.

Explanation:
The given question requires us to calculate the number of litres of N/10 solution that can be prepared from 63gm of oxalic acid. To do this, we need to calculate the molecular weight of oxalic acid, the number of moles of oxalic acid and the volume of N/10 solution.

Firstly, we calculated the molecular weight of oxalic acid by adding the atomic weights of all the atoms present in the molecule. Next, we calculated the number of moles of oxalic acid by dividing the weight of oxalic acid by its molecular weight.

Then, we calculated the volume of N/10 solution required by dividing the number of moles of solute by the normality of the solution. Finally, we arrived at the answer that 0.699 litres of N/10 solution can be prepared from 63gm of oxalic acid.