JEE Exam  >  JEE Questions  >  PASSAGE-1p-Amino-N, N-dimethylaniline is adde... Start Learning for Free
PASSAGE-1
p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of  X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)
Q. The compound X is 
  • a)
    NaNO3
  • b)
    NaCl
  • c)
    Na2SO4
  • d)
    Na2S
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic so...
Reaction of Y indicates that it is Fe3+ salt.
NOTE : since the product formed (methylene blue) has sulphur in its structure, it should be supplied by the compound X which is thus Na2S.
Thus
View all questions of this test
Most Upvoted Answer
PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic so...
Explanation:
Identification of X:
- p-Amino-N, N-dimethylaniline is added to X, which is a strongly acidic solution.
- The formation of methylene blue indicates the presence of reducing agents in X.
- Therefore, X is expected to contain anions that can act as reducing agents, such as sulfite (SO32-), bisulfite (HSO3-), or thiosulfate (S2O32-).
- Among the given options, only Na2S can produce such anions in an acidic solution.
- Hence, the compound X is Na2S.

Identification of Y:
- The addition of Y to the solution of X and p-Amino-N, N-dimethylaniline results in the formation of methylene blue.
- Methylene blue is a cationic dye that forms a complex with anions such as chloride, bromide, or iodide to produce a blue coloration.
- Therefore, Y is expected to be a soluble salt containing one of these anions.
- Among the given options, only NaCl is a soluble salt containing chloride ions.
- Hence, the compound Y is NaCl.

Identification of Z:
- The treatment of Y with potassium hexacyanoferrate(III) results in the formation of a brown coloration due to the formation of Z.
- The brown coloration indicates the presence of Fe(III) ions.
- The reaction between Fe(III) ions and chloride ions produces a brown complex, FeCl63-.
- Therefore, Z is expected to be a compound containing Fe(III) ions and chloride ions.
- Among the given options, only FeCl3 is a compound containing Fe(III) ions and chloride ions.
- Hence, the compound Z is FeCl3.
Explore Courses for JEE exam

Similar JEE Doubts

PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer?
Question Description
PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer?.
Solutions for PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice PASSAGE-1p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z. (2009)Q.The compound X isa)NaNO3b)NaClc)Na2SO4d)Na2SCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev