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A jet of water with cross section of 6 cm2 strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall is
- a)0.864 Nt
- b)86.4 Nt
- c)72 Nt
- d)7.2 Nt
Correct answer is option 'B'. Can you explain this answer?
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A jet of water with cross section of 6 cm2strikes a wall at an angle o...
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A jet of water with cross section of 6 cm2strikes a wall at an angle o...
°. If the velocity of the water jet is 10 m/s, what is the force exerted on the wall?
We can use the formula for force:
Force = mass x acceleration
To find the mass of the water, we need to know the volume of water that hits the wall per second. We can calculate this using the cross-sectional area of the jet and the velocity:
Volume = area x velocity
Volume = 6 cm2 x 10 m/s = 0.006 m3/s
To find the mass, we need to multiply by the density of water:
Mass = volume x density
Mass = 0.006 m3/s x 1000 kg/m3 = 6 kg/s
Now we need to find the acceleration of the water as it hits the wall. We can use trigonometry to find the component of velocity perpendicular to the wall:
Velocity perpendicular = velocity x sin(60°) = 10 m/s x 0.866 = 8.66 m/s
The acceleration will be the change in velocity over time, but since the water stops when it hits the wall, we can use the final velocity of 0 and the initial velocity of 8.66 m/s:
Acceleration = (0 - 8.66 m/s) / 1 s = -8.66 m/s2
(Note that the negative sign indicates that the acceleration is in the opposite direction to the initial velocity.)
Now we can calculate the force:
Force = mass x acceleration
Force = 6 kg/s x -8.66 m/s2 = -52 N
(Note that the negative sign indicates that the force is in the opposite direction to the initial velocity.)
So the force exerted on the wall by the water jet is 52 N.
We can use the formula for force:
Force = mass x acceleration
To find the mass of the water, we need to know the volume of water that hits the wall per second. We can calculate this using the cross-sectional area of the jet and the velocity:
Volume = area x velocity
Volume = 6 cm2 x 10 m/s = 0.006 m3/s
To find the mass, we need to multiply by the density of water:
Mass = volume x density
Mass = 0.006 m3/s x 1000 kg/m3 = 6 kg/s
Now we need to find the acceleration of the water as it hits the wall. We can use trigonometry to find the component of velocity perpendicular to the wall:
Velocity perpendicular = velocity x sin(60°) = 10 m/s x 0.866 = 8.66 m/s
The acceleration will be the change in velocity over time, but since the water stops when it hits the wall, we can use the final velocity of 0 and the initial velocity of 8.66 m/s:
Acceleration = (0 - 8.66 m/s) / 1 s = -8.66 m/s2
(Note that the negative sign indicates that the acceleration is in the opposite direction to the initial velocity.)
Now we can calculate the force:
Force = mass x acceleration
Force = 6 kg/s x -8.66 m/s2 = -52 N
(Note that the negative sign indicates that the force is in the opposite direction to the initial velocity.)
So the force exerted on the wall by the water jet is 52 N.
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A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer?.
A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A jet of water with cross section of 6 cm2strikes a wall at an angle of 60º to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m/s, the force acting on the wall isa)0.864 Ntb)86.4 Ntc)72 Ntd)7.2 NtCorrect answer is option 'B'. Can you explain this answer?.
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