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The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?
- a)13.6
- b)11.3
- c)8.3
- d)14.5
Correct answer is option 'D'. Can you explain this answer?
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The first ionisation potentials of four consecutive elements, present ...
First Ionization Potential (IE): An Introduction
The first ionization potential (IE) is the minimum amount of energy required to remove the most loosely held electron from an isolated gaseous atom to form a cation. In other words, it is the energy required to convert an atom into a positively charged ion by removing its outermost electron.
Given Information:
The first ionization potentials for four consecutive elements in the second period of the periodic table are as follows:
- Element 1: IE = 8.3 eV
- Element 2: IE = 11.3 eV
- Element 3: IE = 14.5 eV
- Element 4: IE = 13.6 eV
Determining the Element: Step-by-Step Explanation
Step 1: Understanding the Periodic Table
The second period of the periodic table consists of the elements:
- Lithium (Li)
- Beryllium (Be)
- Boron (B)
- Carbon (C)
- Nitrogen (N)
- Oxygen (O)
- Fluorine (F)
- Neon (Ne)
Step 2: Mapping Ionization Potentials to Elements
By comparing the given ionization potentials with the elements in the second period of the periodic table, we can determine the corresponding element for each value.
- Element 1 with IE = 8.3 eV: This value matches the ionization potential of lithium (Li).
- Element 2 with IE = 11.3 eV: This value matches the ionization potential of beryllium (Be).
- Element 3 with IE = 14.5 eV: This value matches the ionization potential of boron (B).
- Element 4 with IE = 13.6 eV: This value matches the ionization potential of carbon (C).
Step 3: Finding the First Ionization Potential of Nitrogen
Since the given question asks for the first ionization potential of nitrogen (N), we need to determine the correct value from the given options. The options are:
a) 13.6 eV
b) 11.3 eV
c) 8.3 eV
d) 14.5 eV
By comparing the ionization potentials of the known elements in the second period with the options, we find that:
- The ionization potential of carbon (C) is 13.6 eV.
- The ionization potential of nitrogen (N) is not given in the options.
Therefore, the correct answer is option 'D' (14.5 eV) since it corresponds to the ionization potential of boron (B), which is the element preceding nitrogen (N) in the second period of the periodic table.
Summary:
The first ionization potential of nitrogen (N) is not explicitly given in the options. By comparing the ionization potentials of the known elements in the second period, we can determine that the correct answer is option 'D' (14.5 eV) since it corresponds to the ionization potential of boron (B), the element preceding nitrogen (N) in the periodic table.
The first ionization potential (IE) is the minimum amount of energy required to remove the most loosely held electron from an isolated gaseous atom to form a cation. In other words, it is the energy required to convert an atom into a positively charged ion by removing its outermost electron.
Given Information:
The first ionization potentials for four consecutive elements in the second period of the periodic table are as follows:
- Element 1: IE = 8.3 eV
- Element 2: IE = 11.3 eV
- Element 3: IE = 14.5 eV
- Element 4: IE = 13.6 eV
Determining the Element: Step-by-Step Explanation
Step 1: Understanding the Periodic Table
The second period of the periodic table consists of the elements:
- Lithium (Li)
- Beryllium (Be)
- Boron (B)
- Carbon (C)
- Nitrogen (N)
- Oxygen (O)
- Fluorine (F)
- Neon (Ne)
Step 2: Mapping Ionization Potentials to Elements
By comparing the given ionization potentials with the elements in the second period of the periodic table, we can determine the corresponding element for each value.
- Element 1 with IE = 8.3 eV: This value matches the ionization potential of lithium (Li).
- Element 2 with IE = 11.3 eV: This value matches the ionization potential of beryllium (Be).
- Element 3 with IE = 14.5 eV: This value matches the ionization potential of boron (B).
- Element 4 with IE = 13.6 eV: This value matches the ionization potential of carbon (C).
Step 3: Finding the First Ionization Potential of Nitrogen
Since the given question asks for the first ionization potential of nitrogen (N), we need to determine the correct value from the given options. The options are:
a) 13.6 eV
b) 11.3 eV
c) 8.3 eV
d) 14.5 eV
By comparing the ionization potentials of the known elements in the second period with the options, we find that:
- The ionization potential of carbon (C) is 13.6 eV.
- The ionization potential of nitrogen (N) is not given in the options.
Therefore, the correct answer is option 'D' (14.5 eV) since it corresponds to the ionization potential of boron (B), which is the element preceding nitrogen (N) in the second period of the periodic table.
Summary:
The first ionization potential of nitrogen (N) is not explicitly given in the options. By comparing the ionization potentials of the known elements in the second period, we can determine that the correct answer is option 'D' (14.5 eV) since it corresponds to the ionization potential of boron (B), the element preceding nitrogen (N) in the periodic table.
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The first ionisation potentials of four consecutive elements, present ...
Ans is c because in period energy increase but in nitrogen is hreater energy as compared to oxygen so by this question you see that correct answer is c
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The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer?
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The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer?.
The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer?.
Solutions for The first ionisation potentials of four consecutive elements, present in the second period of the periodic table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?a)13.6b)11.3c)8.3d)14.5Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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