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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.
- a)-55.1
- b)55.1
- c)66.1
- d)-66.1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A resistance of 7 ohm is connected in series with an inductance of 31....
φ=tan-1(XL/R)=55.1
Since this is an inductive circuit, the current will lag, hence φ= -55.1.
Since this is an inductive circuit, the current will lag, hence φ= -55.1.
Most Upvoted Answer
A resistance of 7 ohm is connected in series with an inductance of 31....
Impedance Calculation
- Calculate the impedance of the inductor using the formula: XL = 2πfL
- XL = 2 * π * 50 * 31.8mH ≈ 10 ohm
- Total impedance (Z) = √(R^2 + XL^2)
- Z = √(7^2 + 10^2) ≈ 12.21 ohm
Phase Difference Calculation
- Calculate the phase angle using the formula: φ = arctan(XL/R)
- φ = arctan(10/7) ≈ 55.1 degrees
- Since the resistance is in series with the inductor, the phase difference between the voltage and current in the circuit is 55.1 degrees.
- The correct answer is option 'A' (-55.1 degrees).
- Calculate the impedance of the inductor using the formula: XL = 2πfL
- XL = 2 * π * 50 * 31.8mH ≈ 10 ohm
- Total impedance (Z) = √(R^2 + XL^2)
- Z = √(7^2 + 10^2) ≈ 12.21 ohm
Phase Difference Calculation
- Calculate the phase angle using the formula: φ = arctan(XL/R)
- φ = arctan(10/7) ≈ 55.1 degrees
- Since the resistance is in series with the inductor, the phase difference between the voltage and current in the circuit is 55.1 degrees.
- The correct answer is option 'A' (-55.1 degrees).
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Question Description
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer?.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.a)-55.1b)55.1c)66.1d)-66.1Correct answer is option 'A'. Can you explain this answer?.
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