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PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer?.

Solutions for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is a)b)c)d)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.