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Consider the following
The interior angles of a polygon of n sides are in AP. The smallest angle is 120° and the common difference is 5°.
Q. What is the largest interior angle of the polygon?
  • a)
    160° only
  • b)
    195° only
  • c)
    Either 160° or 195°
  • d)
    Nither 160 nor 195°
Correct answer is option 'A'. Can you explain this answer?
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Consider the followingThe interior angles of a polygon of n sides are ...
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Consider the followingThe interior angles of a polygon of n sides are ...
Explanation:

Given Information:
- Smallest angle of the polygon = 120°
- Common difference between interior angles = 5°

Concept:
- The sum of interior angles of a polygon with n sides is given by the formula (n-2)*180°.
- In an arithmetic progression, the sum of angles is equal to the number of sides multiplied by the average of the first and last angles.

Finding the Largest Angle:
- Let the largest angle be x°.
- Since the smallest angle is 120° and the common difference is 5°, the second smallest angle is 120 + 5 = 125°.
- The average of the first and last angles in an AP is (120 + x)/2.
- The sum of angles of the polygon with n sides is n*(120 + x)/2.
- This sum is also equal to (n-2)*180°.
- Equating the two expressions for the sum of angles, we get: n*(120 + x)/2 = (n-2)*180
- Solving this equation, we get x = 160°.

Conclusion:
- Therefore, the largest interior angle of the polygon is 160°.
- Hence, the correct answer is option 'a) 160° only'.
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Consider the followingThe interior angles of a polygon of n sides are in AP. The smallest angle is 120° and the common difference is 5°.Q. What is the largest interior angle of the polygon?a)160° onlyb)195° onlyc)Either 160° or 195°d)Nither 160 nor 195°Correct answer is option 'A'. Can you explain this answer?
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