**Finding the Equations of the Lines:**

To find the equations of the lines, we need to determine the slope and the y-intercept of each line. Given that the lines intersect the x-axis at distances of 4 and -4, we can deduce that the y-intercepts are 4 and -4 respectively. Furthermore, since the lines intersect the y-axis at distances of 2 and 6, we can conclude that the x-intercepts are 2 and 6 respectively.

The general equation of a line is given by y = mx + c, where m represents the slope and c represents the y-intercept. Let's denote the equations of the two lines as Line 1 and Line 2.

**Line 1:**
The x-intercept of Line 1 is 2, which means that when x = 2, y = 0. Using this information, we can substitute the values into the equation y = mx + c:

0 = m(2) + c

Simplifying the equation, we get:
c = -2m

Therefore, the equation of Line 1 is y = mx - 2m.

**Line 2:**
Similarly, the x-intercept of Line 2 is 6, which means that when x = 6, y = 0. Substituting these values into the equation y = mx + c:

0 = m(6) + c

Simplifying the equation, we get:
c = -6m

Hence, the equation of Line 2 is y = mx - 6m.

**Finding the Point of Intersection:**

To find the point of intersection, we need to solve the two equations simultaneously. By equating the two equations of the lines, we can determine the values of x and y at the point of intersection.

Substituting the equations of Line 1 and Line 2, we have:
mx - 2m = mx - 6m

Simplifying the equation, we get:
4m = 0

This implies that m = 0.

Substituting this value back into either equation, we can solve for y:
y = 0 - 2(0)
y = 0

Thus, the coordinates of the point of intersection are (0, 0).