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Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer?.

Solutions for Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Assuming that water vapour is an ideal gas, the internal energy change (ΔU) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (given : molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol–1 and R = 8.3 J mol–1 K–1) will be [2007]a)41.00 kJ mol–1b)4.100 kJ mol–1c)3.7904 kJ mol–1d)37.904 kJ mol–1Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.