Class 11 Exam > Class 11 Questions > Two balls are thrown simultaneously from the ...
Start Learning for Free
Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular?
Most Upvoted Answer
Two balls are thrown simultaneously from the same point horizontally i...
Explanation:
When two balls are thrown horizontally in opposite directions, their vertical components of velocity are zero. Therefore, the only relative motion between the balls is in the horizontal direction. Let's assume that the distance between the balls at the time when their velocities are perpendicular is d.
Calculating the time:
To calculate the time at which the velocities of the balls are perpendicular, we need to use the concept of relative velocity. The relative velocity of ball 1 with respect to ball 2 is (V1 + V2), as both balls are moving in opposite directions. Therefore, the time taken for the balls to reach the point where their velocities are perpendicular is given by the formula:
t = d / (V1 + V2)
Calculating the distance:
To find the distance between the balls at this moment, we need to calculate the distance covered by each ball in this time. The distance covered by ball 1 is given by:
d1 = V1 * t = V1 * d / (V1 + V2)
Similarly, the distance covered by ball 2 is given by:
d2 = V2 * t = V2 * d / (V1 + V2)
Therefore, the distance between the balls when their velocities are perpendicular is given by:
d = d1 + d2 = V1 * d / (V1 + V2) + V2 * d / (V1 + V2)
Simplifying this equation, we get:
d = (V1 * V2 * t) / (V1 + V2)
Substituting the value of t in terms of d, we get:
d = (V1 * V2 * d) / [(V1 + V2)^2]
Simplifying this equation, we get:
d = (V1 * V2) / (V1 + V2)
Therefore, the distance between the balls when their velocities are perpendicular is:
d = (V1 * V2) / (V1 + V2) = (3 * 4) / (3 + 4) = 12 / 7 meters
Conclusion:
Hence, the distance between the balls at the moment when their velocities are perpendicular is 12/7 meters.
When two balls are thrown horizontally in opposite directions, their vertical components of velocity are zero. Therefore, the only relative motion between the balls is in the horizontal direction. Let's assume that the distance between the balls at the time when their velocities are perpendicular is d.
Calculating the time:
To calculate the time at which the velocities of the balls are perpendicular, we need to use the concept of relative velocity. The relative velocity of ball 1 with respect to ball 2 is (V1 + V2), as both balls are moving in opposite directions. Therefore, the time taken for the balls to reach the point where their velocities are perpendicular is given by the formula:
t = d / (V1 + V2)
Calculating the distance:
To find the distance between the balls at this moment, we need to calculate the distance covered by each ball in this time. The distance covered by ball 1 is given by:
d1 = V1 * t = V1 * d / (V1 + V2)
Similarly, the distance covered by ball 2 is given by:
d2 = V2 * t = V2 * d / (V1 + V2)
Therefore, the distance between the balls when their velocities are perpendicular is given by:
d = d1 + d2 = V1 * d / (V1 + V2) + V2 * d / (V1 + V2)
Simplifying this equation, we get:
d = (V1 * V2 * t) / (V1 + V2)
Substituting the value of t in terms of d, we get:
d = (V1 * V2 * d) / [(V1 + V2)^2]
Simplifying this equation, we get:
d = (V1 * V2) / (V1 + V2)
Therefore, the distance between the balls when their velocities are perpendicular is:
d = (V1 * V2) / (V1 + V2) = (3 * 4) / (3 + 4) = 12 / 7 meters
Conclusion:
Hence, the distance between the balls at the moment when their velocities are perpendicular is 12/7 meters.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular?
Question Description
Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular?.
Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular?.
Solutions for Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? defined & explained in the simplest way possible. Besides giving the explanation of
Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular?, a detailed solution for Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? has been provided alongside types of Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? theory, EduRev gives you an
ample number of questions to practice Two balls are thrown simultaneously from the same point horizontally in same opposite direction with velocities V1 equal to 3 metre per second and V2 equal to 4 metre per second find the distance between them that moment when the velocity seem to be mutually perpendicular? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup