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A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]
- a)violates 1st law of thermodynamics
- b)violates 1st law of themodynamics if Q1 is –ve
- c)violates 1st law of thermodynamics of Q2 is –ve
- d)does not violate 1st law of themodynamics.
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at tempera...
According to first law of thermodynamics energy can neither be created nor destroyed although it can be converted from one form to another.
NOTE : Carnot cycle is based upon this principle but ΔUring the conversion of heat into work some mechanical energy is always converted to other form of energy hence this data violates 1st law of thermodynamics.
NOTE : Carnot cycle is based upon this principle but ΔUring the conversion of heat into work some mechanical energy is always converted to other form of energy hence this data violates 1st law of thermodynamics.
Most Upvoted Answer
A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at tempera...
A) The data does not necessarily violate the first law of thermodynamics. The first law states that energy cannot be created or destroyed, only transferred or transformed. In this case, the engine absorbs heat Q1 at temperature T1 and heat Q2 at temperature T2. The work done by the engine is J (Q1 - Q2). As long as the total energy input (Q1 + Q2) is equal to the total work output (J), the first law of thermodynamics is not violated.
b) The data would violate the first law of thermodynamics if Q1 is greater than Q2 and the work done by the engine is negative. In this case, it would mean that the engine is somehow generating more energy (Q1) than it is absorbing (Q2), which would violate the conservation of energy principle.
b) The data would violate the first law of thermodynamics if Q1 is greater than Q2 and the work done by the engine is negative. In this case, it would mean that the engine is somehow generating more energy (Q1) than it is absorbing (Q2), which would violate the conservation of energy principle.
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A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer?
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A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer?.
A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A heat engine abosrbs heat Q1 at temperature T1 and heat Q2 at temperature T2. Work done by the engine is J (Q1 + Q2). This data [2002]a)violates 1st law of thermodynamicsb)violates 1st law of themodynamics if Q1 is –vec)violates 1st law of thermodynamics of Q2 is –ved)does not violate 1st law of themodynamics.Correct answer is option 'A'. Can you explain this answer?.
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