For complete combustion of ethanol, C2H5OH (l) + 3O2(g)andmdash;andrarr; 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ molandndash;1 at 25andordm;C. Assuming ideality the enthalpy of combustion, andDelta;cH, for the reaction will be: (R = 8.314 kJ molandndash;1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer?

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For complete combustion of ethanol, C₂H₅OH (l) + 3O₂(g)—→ 2CO₂ ( g)+ 3H₂O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol^–1at 25ºC. Assuming ideality the enthalpy of combustion, Δ_cH, for the reaction will be: (R = 8.314 kJ mol^–1) [JEE M 2014]

a)
-1366.95 kJ mol^-1
b)
-1361.95 kJ mol^-1
c)
-1460.95 kJ mol^-1
d)
-1350.50 kJ mol^-1

Correct answer is option 'A'. Can you explain this answer?

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For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—&...

C₂ H₅OH(l) + 3O₂( g)→ 2CO₂( g ) + 3H₂O(l)

Bomb calorimeter gives ΔU of the reaction

Given, ΔU = –1364.47 kJ mol^–1

Δn_g = – 1 ΔH = ΔU + Δn_gRT

= 1364.47 -

= – 1366.93 kJ mol^–1

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For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer?

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For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer?.

Solutions for For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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