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For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer?.

Solutions for For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For complete combustion of ethanol, C2H5OH (l) + 3O2(g)—​→ 2CO2 ( g)+ 3H2O (l), the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol–1 at 25ºC. Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be: (R = 8.314 kJ mol–1) [JEE M 2014]a)-1366.95 kJ mol-1b)-1361.95 kJ mol-1c)-1460.95 kJ mol-1d)-1350.50 kJ mol-1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.