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One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 is
- a)-7.53 KJ-mol-1
- b)-16.1 KJ-mol-1
- c)-398.1 KJ-mol-1
- d)-602 KJ-mol-1
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Tempera...
ΔU = - 6.12 x 1.23 x GMM (NH4NO3)
= - 6.12 x 1.23 x 80 = - 602.208 kJ mol-1
= - 6.12 x 1.23 x 80 = - 602.208 kJ mol-1
Most Upvoted Answer
One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Tempera...
Given:
- Mass of NH4NO3 = 1 gram
- Temperature increase in the calorimeter = 6.12 K
- Heat capacity of the system = 1.23 KJ/g-1 - deg-1
To find:
- Molar heat of decomposition for NH4NO3
Concept:
The heat capacity of a system is defined as the amount of heat required to raise the temperature of the system by 1 degree Celsius or 1 Kelvin.
The molar heat of decomposition can be calculated using the equation:
Molar heat of decomposition = (Heat capacity of the system * Mass of NH4NO3 * Temperature increase) / Molar mass of NH4NO3
Calculation:
1. Calculate the molar mass of NH4NO3:
NH4NO3 = (1 * 14.01) + (4 * 1.01) + 14.01 + (3 * 16.00)
= 80.04 g/mol
2. Substitute the given values into the equation:
Molar heat of decomposition = (1.23 KJ/g-1 - deg-1 * 1 g * 6.12 K) / 80.04 g/mol
3. Simplify the expression:
Molar heat of decomposition = (1.23 KJ * 6.12 K) / 80.04 g/mol
= 7.53 KJ/mol
Answer:
Therefore, the molar heat of decomposition for NH4NO3 is -7.53 KJ/mol, which is option (D).
- Mass of NH4NO3 = 1 gram
- Temperature increase in the calorimeter = 6.12 K
- Heat capacity of the system = 1.23 KJ/g-1 - deg-1
To find:
- Molar heat of decomposition for NH4NO3
Concept:
The heat capacity of a system is defined as the amount of heat required to raise the temperature of the system by 1 degree Celsius or 1 Kelvin.
The molar heat of decomposition can be calculated using the equation:
Molar heat of decomposition = (Heat capacity of the system * Mass of NH4NO3 * Temperature increase) / Molar mass of NH4NO3
Calculation:
1. Calculate the molar mass of NH4NO3:
NH4NO3 = (1 * 14.01) + (4 * 1.01) + 14.01 + (3 * 16.00)
= 80.04 g/mol
2. Substitute the given values into the equation:
Molar heat of decomposition = (1.23 KJ/g-1 - deg-1 * 1 g * 6.12 K) / 80.04 g/mol
3. Simplify the expression:
Molar heat of decomposition = (1.23 KJ * 6.12 K) / 80.04 g/mol
= 7.53 KJ/mol
Answer:
Therefore, the molar heat of decomposition for NH4NO3 is -7.53 KJ/mol, which is option (D).
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One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer?
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One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer?.
One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram sample of NH4NO3 is decomposed in a bomb-calorimeter. Temperature of the calorimeter increases by 6.12 K. Heat capacity of the system is 1.23 KJ-g-1 - deg-1. What is the molar heat of decomposition for NH4NO3 isa)-7.53 KJ-mol-1b)-16.1 KJ-mol-1c)-398.1 KJ-mol-1d)-602 KJ-mol-1Correct answer is option 'D'. Can you explain this answer?.
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