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In Young's double slit experiment, the width of the fringes obtained with light of wavelength 6000 Angstrom is 2.0mm. The fringe width, if the entire apparatus is immersed in a liquid of refractive index 1.33, will be
  • a)
    1.5 m
  • b)
    1.5 cm
  • c)
    1.5 mm
  • d)
    1.5 km
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In Young's double slit experiment, the width of the fringes obtain...
Fringe width in Young's double slit experiment β = Dλ/d
When apparatus is immersed in liquid, only wavelength of light (λ) changes
Wavelength of light is liquid,
λ' = λ n , where n = refractive index of medium
Initial fringe width, β = Dλ/d .....(i)
Fringe width in liquid, β' = Dλ'/d .....(ii)
Dividing Equation (ii) by Equation (i), we get
β'/β = λ'/λ
The new fringe width, β' = 2.0/1.33 mm = 1.5 mm
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In Young's double slit experiment, the width of the fringes obtained with light of wavelength 6000 Angstrom is 2.0mm. The fringe width, if the entire apparatus is immersed in a liquid of refractive index 1.33, will bea)1.5 mb)1.5 cmc)1.5 mmd)1.5 kmCorrect answer is option 'C'. Can you explain this answer?
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