The two consecutive class marks of a distribution are 52 and 57. find ...
Class size = Difference between consecutive class marks = 57-52
lower class limit = 52 - 5/2 = 49.5
upper class limit = 52 + 5/2 = 54.5
The two consecutive class marks of a distribution are 52 and 57. find ...
Introduction:
In a frequency distribution, class marks represent the midpoint values of each class interval. The class mark is the average of the lower and upper class limits. Given that the two consecutive class marks are 52 and 57, we can determine the class limits using this information.
Steps to find the class limits:
Step 1: Determine the class interval
To find the class interval, we subtract the lower class mark from the higher class mark:
Class interval = Higher class mark - Lower class mark
In this case, the class interval is:
Class interval = 57 - 52 = 5
Step 2: Determine the lower class limit
To find the lower class limit, we subtract half of the class interval from the lower class mark:
Lower class limit = Lower class mark - (Class interval / 2)
In this case, the lower class limit is:
Lower class limit = 52 - (5 / 2) = 52 - 2.5 = 49.5
Step 3: Determine the upper class limit
To find the upper class limit, we add half of the class interval to the higher class mark:
Upper class limit = Higher class mark + (Class interval / 2)
In this case, the upper class limit is:
Upper class limit = 57 + (5 / 2) = 57 + 2.5 = 59.5
Conclusion:
Therefore, the class limits for the given distribution are 49.5 and 59.5. The lower class limit represents the smallest value in the class interval, while the upper class limit represents the largest value in the class interval.