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Latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10.00 Kcal/mol. What will be the change in internal energy (ΔU) of 3 mol of liquid at same temperature ?a)13.0 Kcalb)-13.0 Kcalc)27.0 Kcald)-27.0 KcalCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10.00 Kcal/mol. What will be the change in internal energy (ΔU) of 3 mol of liquid at same temperature ?a)13.0 Kcalb)-13.0 Kcalc)27.0 Kcald)-27.0 KcalCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10.00 Kcal/mol. What will be the change in internal energy (ΔU) of 3 mol of liquid at same temperature ?a)13.0 Kcalb)-13.0 Kcalc)27.0 Kcald)-27.0 KcalCorrect answer is option 'C'. Can you explain this answer?.

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