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A 0.004 M solution of Na2SO4 is isotonic with 0.010 M solution of glucose at same temperature. The  percentage dissociation of Na2SO4 is
  • a)
    25%
  • b)
    50%
  • c)
    75%
  • d)
    85%
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A 0.004 M solution of Na2SO4 is isotonic with 0.010 M solution of gluc...
Correct option (C) 75%
Explanation:
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A 0.004 M solution of Na2SO4 is isotonic with 0.010 M solution of gluc...
Given Information:
- Concentration of Na2SO4 solution = 0.004 M
- Concentration of glucose solution = 0.010 M
- Both solutions are isotonic at the same temperature

Calculating Osmolarity:
1. Osmolarity of Na2SO4 solution = 2 * 0.004 = 0.008 osmol/L
2. Osmolarity of glucose solution = 1 * 0.010 = 0.010 osmol/L

Understanding Isotonic Solutions:
- Isotonic solutions have the same osmolarity and exert the same osmotic pressure.
- If two solutions are isotonic, it means they have the same concentration of solute particles.

Relationship Between Osmolarity and Dissociation:
- For Na2SO4, it dissociates into 3 ions in solution (2Na+ and 1SO4^2-).
- For glucose, it does not dissociate in solution.

Calculating Percentage Dissociation:
- If the solutions are isotonic, the total number of particles in Na2SO4 solution must be equal to the total number of particles in the glucose solution.
- Since Na2SO4 dissociates into 3 particles, the percentage dissociation can be calculated as follows:
- (0.008 x 3) / 0.010 = 0.024 / 0.010 = 2.4
- Percentage dissociation = (2.4 / 3) x 100% = 80%

Conclusion:
- The percentage dissociation of Na2SO4 in the given scenario is 80%.
- The closest option provided is 75%, which is the correct answer.
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A 0.004 M solution of Na2SO4 is isotonic with 0.010 M solution of glucose at same temperature. The percentage dissociation of Na2SO4 isa)25%b)50%c)75%d)85%Correct answer is option 'C'. Can you explain this answer?
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