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Number of X is randomly selected from the set of odd numbers and Y is randomly selected from the set of even numbers of the set {1,2,3,4,5,6,7}.LetZ = (X+Y)..​
What is P(Z= 10) equal to ?
  • a)
    0
  • b)
    1/2
  • c)
    1/3
  • d)
    1/5
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Number of X is randomly selected from the set of odd numbers and Y is ...
Set A = {1 ,2 ,3 ,4 ,5 ,6 ,7 } and z =x + y
x = set of odd numbers
y = set of even numbers
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Most Upvoted Answer
Number of X is randomly selected from the set of odd numbers and Y is ...
Explanation:

Given:
- X is randomly selected from the set of odd numbers {1, 3, 5, 7}
- Y is randomly selected from the set of even numbers {2, 4, 6}

Finding P(Z = 10):
- The possible values of Z are the sum of an odd number and an even number from the given sets.
- The only combination that gives a sum of 10 is when X = 3 and Y = 7.
- Therefore, the probability of Z being equal to 10 is 0, as there is only one favorable outcome out of all possible outcomes.
Therefore, the correct answer is option A) 0, as the probability of Z being equal to 10 is 0.
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Number of X is randomly selected from the set of odd numbers and Y is randomly selected from the set of even numbers of the set {1,2,3,4,5,6,7}.LetZ = (X+Y)..​What is P(Z= 10) equal to ?a)0b)1/2c)1/3d)1/5Correct answer is option 'A'. Can you explain this answer?
Question Description
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