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A 1 hour rainfall of 10 cm has return period of 50 year. The probability that 1 hour of rainfall 10 cm or more will occur in each of two successive years is
  • a)
    0.04
  • b)
    0.2
  • c)
    0.3
  • d)
    0.0004
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A 1 hour rainfall of 10 cm has return period of 50 year. The probabili...
Return period of rainfall, T = 50 years
 Probability of occurrence once in 50 years, p=1/50 =0.02
Probability of occurrence in each of 2 successive years
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Most Upvoted Answer
A 1 hour rainfall of 10 cm has return period of 50 year. The probabili...
Given information:
- 1 hour rainfall of 10 cm has a return period of 50 years

To find:
- Probability of 1 hour or more rainfall of 10 cm occurring in each of two successive years

Solution:

Definition of return period:
The return period of an extreme event is the average time between occurrences of an event of equal or greater magnitude.

From the given information, we know that a 1 hour rainfall of 10 cm has a return period of 50 years. This means that in a given year, the probability of this extreme event occurring is 1/50 or 0.02.

Probability of 1 hour or more rainfall of 10 cm occurring in two successive years:

Since we want to find the probability of this extreme event occurring in two successive years, we can use the following formula:

P(A and B) = P(A) x P(B|A)

- P(A) = Probability of the extreme event occurring in year 1
- P(B|A) = Probability of the extreme event occurring in year 2, given that it occurred in year 1

Probability of the extreme event occurring in year 1:

Since the event has a return period of 50 years, the probability of it occurring in a given year is 1/50 or 0.02. Therefore,

P(A) = 0.02

Probability of the extreme event occurring in year 2, given that it occurred in year 1:

If the extreme event occurred in year 1, the probability of it occurring again in year 2 is still 0.02 since the events are independent of each other. Therefore,

P(B|A) = 0.02

Using the formula above, we can find the probability of the extreme event occurring in two successive years:

P(A and B) = P(A) x P(B|A)
P(A and B) = 0.02 x 0.02
P(A and B) = 0.0004

Therefore, the probability of 1 hour or more rainfall of 10 cm occurring in each of two successive years is 0.0004 or 0.04%.

Answer: Option D (0.0004)
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A 1 hour rainfall of 10 cm has return period of 50 year. The probability that 1 hour of rainfall 10 cm or more will occur in each of two successive years isa)0.04b)0.2c)0.3d)0.0004Correct answer is option 'D'. Can you explain this answer?
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