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The mass of flywheel of a steam engine is 3250 kg with the radius of gyration of 1 m. The starting torque of the engine is 4500 N - m. What is the angular acceleration (rad/s2) of the flywheel?
- a)3.4
- b)2
- c)2.48
- d)1.38
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The mass of flywheel of a steam engine is 3250 kg with the radius of g...
Mass moment of inertia of the flywheel:
I = mk2 = 3250 × 12 = 3250 kg-m2
Starting torque of the engine: T = I.α
Angular acceleration of the flywheel:
α = T/I = 4500/3250 = 18/13 = 1.38 rad/s2
Most Upvoted Answer
The mass of flywheel of a steam engine is 3250 kg with the radius of g...
To find the angular acceleration of the flywheel, we can use the formula:
Torque = Moment of inertia * Angular acceleration
Given:
Mass of flywheel (m) = 3250 kg
Radius of gyration (k) = 1 m
Torque (T) = 4500 N - m
We can calculate the moment of inertia (I) using the formula:
Moment of inertia (I) = m * k^2
Plugging in the values, we get:
I = 3250 kg * (1 m)^2 = 3250 kg * 1 m^2 = 3250 kg * m^2
Now, we can rearrange the formula to solve for angular acceleration (α):
Angular acceleration (α) = Torque / Moment of inertia
Plugging in the values, we get:
α = 4500 N - m / (3250 kg * m^2)
Simplifying the expression, we get:
α = 4500 N - m / 3250 kg * m^2
Now, let's calculate the value:
α = 4500 / 3250 ≈ 1.38 rad/s^2
Therefore, the angular acceleration of the flywheel is approximately 1.38 rad/s^2.
The correct answer is option 'D'.
Torque = Moment of inertia * Angular acceleration
Given:
Mass of flywheel (m) = 3250 kg
Radius of gyration (k) = 1 m
Torque (T) = 4500 N - m
We can calculate the moment of inertia (I) using the formula:
Moment of inertia (I) = m * k^2
Plugging in the values, we get:
I = 3250 kg * (1 m)^2 = 3250 kg * 1 m^2 = 3250 kg * m^2
Now, we can rearrange the formula to solve for angular acceleration (α):
Angular acceleration (α) = Torque / Moment of inertia
Plugging in the values, we get:
α = 4500 N - m / (3250 kg * m^2)
Simplifying the expression, we get:
α = 4500 N - m / 3250 kg * m^2
Now, let's calculate the value:
α = 4500 / 3250 ≈ 1.38 rad/s^2
Therefore, the angular acceleration of the flywheel is approximately 1.38 rad/s^2.
The correct answer is option 'D'.
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The mass of flywheel of a steam engine is 3250 kg with the radius of gyration of 1 m. The starting torque of the engine is 4500 N - m. What is the angular acceleration (rad/s2) of the flywheel?a)3.4b)2c)2.48d)1.38Correct answer is option 'D'. Can you explain this answer?
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