Consider the spheres x2 + y2 + z2 - 4y + 3 = 0 and x2 + y2 + z2 + 2x +...
x
2 + y
2 + z
2- 4y + 3 = 0
x
2 + y
2 - 4y+4 — 4 + z
2+ 3 = 0
x
2 + ( y - 2 )
2 + z
2 = 1 ...
(i) Sphere with centre (0,2,0) and radius 1 unit.
x
2 + y
2 + z
2 + 2x + 4z - 4 = 0
x
2 + 2 x + l-l+ y
2 + z
2 + 4z + 4 - 4 -4 = 0
(x + l)
2 + y
2 + (z + 2)
2 = 32 ...(ii)
Sphere with centre (-1,0, -2) and radius 3 units.
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Consider the spheres x2 + y2 + z2 - 4y + 3 = 0 and x2 + y2 + z2 + 2x +...
To find the distance between the centers of the two spheres, we need to first find the coordinates of the centers of the spheres.
Given Spheres:
1) x^2 + y^2 + z^2 - 4y + 3 = 0 ...(1)
2) x^2 + y^2 + z^2 + 2x + 4z - 4 = 0 ...(2)
To find the center of Sphere 1, we can write the equation of the sphere in the form (x-a)^2 + (y-b)^2 + (z-c)^2 = r^2, where (a,b,c) represents the coordinates of the center and r represents the radius.
1) x^2 + (y^2 - 4y) + z^2 + 3 = 0
x^2 + (y^2 - 4y + 4) + z^2 + 3 = 4
x^2 + (y - 2)^2 + z^2 = 1
Comparing this equation with the standard form, we can see that the center of Sphere 1 is at (0, 2, 0) and the radius is 1.
To find the center of Sphere 2, we can write the equation of the sphere in the form (x-a)^2 + (y-b)^2 + (z-c)^2 = r^2.
2) x^2 + (y^2 + 2x) + z^2 + 4z = 4
(x^2 + 2x + 1) + (y^2) + (z^2 + 4z + 4) = 9
(x + 1)^2 + y^2 + (z + 2)^2 = 9
Comparing this equation with the standard form, we can see that the center of Sphere 2 is at (-1, 0, -2) and the radius is 3.
Therefore, the coordinates of the centers of the two spheres are (0, 2, 0) and (-1, 0, -2).
The distance between two points (x1, y1, z1) and (x2, y2, z2) can be calculated using the distance formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)
Calculating the distance between the centers of the two spheres:
d = sqrt((0 - (-1))^2 + (2 - 0)^2 + (0 - (-2))^2)
= sqrt(1 + 4 + 4)
= sqrt(9)
= 3
Therefore, the distance between the centers of the two spheres is 3 units. Hence, option C is the correct answer.