**Answer:**

To determine which bulb will fuse, we need to consider the power dissipated by each bulb when connected in series to a 440V supply.

**Explanation:**

When bulbs are connected in series, the total voltage across the circuit is divided between the two bulbs. In this case, the total voltage is 440V.

Let's calculate the voltage across each bulb:

Voltage across each bulb = Total voltage / Number of bulbs

Voltage across each bulb = 440V / 2 = 220V

Now, let's calculate the power dissipated by each bulb using the formula:

Power (P) = (Voltage (V))^2 / Resistance (R)

We know that power is given in terms of watts (W), and the voltage is given as 220V for both bulbs. We need to find the resistance of each bulb to calculate the power dissipated.

Using Ohm's Law, we can find the resistance:

Resistance (R) = Voltage (V) / Current (I)

Since we are not given the current, we can assume the resistance of each bulb is constant.

Now, let's calculate the resistance for each bulb:

For the 25W - 220V bulb:
Resistance (R1) = 220V / I1

For the 100W - 220V bulb:
Resistance (R2) = 220V / I2

Since the resistance of each bulb is constant, we can assume the current passing through each bulb is the same.

Now, let's compare the power dissipated by each bulb:

For the 25W - 220V bulb:
Power1 = (220V)^2 / R1

For the 100W - 220V bulb:
Power2 = (220V)^2 / R2

As the power dissipated by each bulb depends on their resistance, it is not possible to determine which bulb will fuse without knowing the resistance values. Therefore, the answer is **D) Neither**.

In summary, without the knowledge of the resistances of the bulbs, we cannot determine which bulb will fuse when connected in series to a 440V supply.

The bulb with power 25w should fuse first..
Bcz when two or more bulb are connected in series the power consumed will be less and resistance of circuit will increase... so the bulb of less power will glow more and on increasing applied voltage it will fuse first..