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Out of the following, the alkene that exhibits optical isomerism is
- a)3-methyl-2-pentene
- b)4-methyl-1-pentene
- c)3-methyl-1-pentene
- d)2-methyl-2-pentene
Correct answer is option 'C'. Can you explain this answer?
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Out of the following, the alkene that exhibits optical isomerism isa)3...
For a compound to show optical isomer ism, presence of chiral carbon atom is a necessary condition.
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Out of the following, the alkene that exhibits optical isomerism isa)3...
Explanation:
To determine if an alkene exhibits optical isomerism, we need to check if it has a chiral carbon atom. A chiral carbon is a carbon atom that is bonded to four different groups or atoms.
Option A: 3-methyl-2-pentene
This alkene has a double bond between the second and third carbon atoms. The second carbon atom is bonded to three hydrogen atoms and one methyl group. The third carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the third carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option A does not exhibit optical isomerism.
Option B: 4-methyl-1-pentene
This alkene has a double bond between the first and second carbon atoms. The first carbon atom is bonded to three hydrogen atoms and one methyl group. The second carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the second carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option B does not exhibit optical isomerism.
Option C: 3-methyl-1-pentene
This alkene has a double bond between the first and second carbon atoms. The first carbon atom is bonded to three hydrogen atoms and one methyl group. The second carbon atom is bonded to two hydrogen atoms, one methyl group, and one propyl group. Since the second carbon atom has four different groups (H, CH3, CH2CH2CH3), it is a chiral carbon. Therefore, option C exhibits optical isomerism.
Option D: 2-methyl-2-pentene
This alkene has a double bond between the second and third carbon atoms. The second carbon atom is bonded to three hydrogen atoms and one methyl group. The third carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the third carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option D does not exhibit optical isomerism.
Therefore, the correct answer is option C, 3-methyl-1-pentene, as it has a chiral carbon atom and exhibits optical isomerism.
To determine if an alkene exhibits optical isomerism, we need to check if it has a chiral carbon atom. A chiral carbon is a carbon atom that is bonded to four different groups or atoms.
Option A: 3-methyl-2-pentene
This alkene has a double bond between the second and third carbon atoms. The second carbon atom is bonded to three hydrogen atoms and one methyl group. The third carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the third carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option A does not exhibit optical isomerism.
Option B: 4-methyl-1-pentene
This alkene has a double bond between the first and second carbon atoms. The first carbon atom is bonded to three hydrogen atoms and one methyl group. The second carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the second carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option B does not exhibit optical isomerism.
Option C: 3-methyl-1-pentene
This alkene has a double bond between the first and second carbon atoms. The first carbon atom is bonded to three hydrogen atoms and one methyl group. The second carbon atom is bonded to two hydrogen atoms, one methyl group, and one propyl group. Since the second carbon atom has four different groups (H, CH3, CH2CH2CH3), it is a chiral carbon. Therefore, option C exhibits optical isomerism.
Option D: 2-methyl-2-pentene
This alkene has a double bond between the second and third carbon atoms. The second carbon atom is bonded to three hydrogen atoms and one methyl group. The third carbon atom is bonded to two hydrogen atoms, one methyl group, and one ethyl group. Since the third carbon atom has two hydrogen atoms, it is not a chiral carbon. Therefore, option D does not exhibit optical isomerism.
Therefore, the correct answer is option C, 3-methyl-1-pentene, as it has a chiral carbon atom and exhibits optical isomerism.
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Out of the following, the alkene that exhibits optical isomerism isa)3-methyl-2-penteneb)4-methyl-1-pentenec)3-methyl-1-pentened)2-methyl-2-penteneCorrect answer is option 'C'. Can you explain this answer?
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