An ideal gas in a thermally insulated vessel at internal pressure = P1, volume = V1 and absolute temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P2, V2 and T2, respectively. For this expansion, (JEE Adv. 2014)a)q = 0b)T2 = T1c)P2V2= P1V1d)P2V2andgamma; = P1V1andgamma;Correct answer is option 'A,B,C'. Can you explain this answer?

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An ideal gas in a thermally insulated vessel at internal pressure = P₁, volume = V₁ and absolute temperature = T₁ expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P₂, V₂ and T₂, respectively. For this expansion, (JEE Adv. 2014)

a)
q = 0
b)
T₂ = T₁
c)
P₂V₂ = P₁V₁
d)
P₂V₂γ = P₁V₁γ

Correct answer is option 'A,B,C'. Can you explain this answer?

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An ideal gas in a thermally insulated vessel at internal pressure = P1...

This is a case of Isothermal Adiabatic Irreversible Expansion.

The process is adiabatic because the system is thermally isolated, therefore
q=0.
Since

Internal energy

The change in internal energy of an ideal gas depends only on temperature and

Hence, the process is isothermal, i.e. T1 = T2
As number of moles and temperature is constant PV is also constant.

is incorrect, as it is valid for Adiabatic Reversible Process.

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An ideal gas in a thermally insulated vessel at internal pressure = P1, volume = V1 and absolute temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P2, V2 and T2, respectively. For this expansion, (JEE Adv. 2014)a)q = 0b)T2 = T1c)P2V2= P1V1d)P2V2γ = P1V1γCorrect answer is option 'A,B,C'. Can you explain this answer?

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