Consider the following statements in respect of the given equation:(x2...
Statement 1: All the roots of the equation are complex.
Statement 2: The sum of all the roots of the equation is 6.
To determine the correctness of these statements, let's analyze the given equation and its roots.
The given equation is:
(x^2 - 2)^2 - 8x^2 = 6x(x^2 - 2)
Simplifying the equation:
(x^4 - 4x^2 + 4) - 8x^2 = 6x^3 - 12x
Rearranging the equation:
x^4 - 12x^3 + 4x^2 + 12x + 4 = 0
Now, let's analyze each statement separately:
Statement 1: All the roots of the equation are complex.
To determine the nature of the roots, we can consider the discriminant of the equation. For a quartic equation of the form ax^4 + bx^3 + cx^2 + dx + e = 0, the discriminant is given by:
Δ = b^2c^2 - 4ac^3 - 4b^3d - 27a^2d^2 + 18abcd
If Δ > 0, the equation has two complex roots and two real roots.
If Δ = 0, the equation has two repeated roots and two real roots.
If Δ < 0,="" the="" equation="" has="" four="" complex="" />
Let's calculate the discriminant for the given equation:
a = 1, b = -12, c = 4, d = 12
Δ = (-12)^2(4)^2 - 4(1)(4)^3 - 4(-12)^3(12) - 27(1)^2(12)^2 + 18(1)(-12)(4)(12)
After simplification, Δ = -3456
Since the discriminant Δ < 0,="" it="" implies="" that="" all="" the="" roots="" of="" the="" equation="" are="" complex.="" hence,="" />Statement 1 is correct.
Statement 2: The sum of all the roots of the equation is 6.
To find the sum of the roots, we can use Vieta's formulas. For a quartic equation of the form ax^4 + bx^3 + cx^2 + dx + e = 0 with roots α, β, γ, and δ, the sum of the roots is given by:
α + β + γ + δ = -b/a
In our equation, a = 1 and b = -12. Therefore, the sum of the roots is:
α + β + γ + δ = -(-12)/1 = 12
Since the sum of the roots is 12, which is not equal to 6, Statement 2 is incorrect.
Hence, the correct answer is Option B: 2 only.