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Which of the following compounds will exhibit geometrical isomerism ?
- a)1-Phenyl-2-butene
- b)3-Phenyl-1-butene
- c)2-Phenyl-1-butene
- d)1,1-Diphenyl-1-propene
Correct answer is option 'A'. Can you explain this answer?
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Which of the following compounds will exhibit geometrical isomerism ?a...
Geometrical Isomerism
Geometrical isomerism is a type of stereoisomerism where isomers have the same molecular formula but differ in the arrangement of atoms in space due to restricted rotation around a bond. It occurs when there is a double bond or a ring in the molecule and two different groups or atoms are attached to each of the carbon atoms forming the double bond or ring.
Explanation of the given options:
Let's analyze each option to determine if it exhibits geometrical isomerism.
a) 1-Phenyl-2-butene:
In this compound, there is a double bond between the second and third carbon atoms. The carbon atoms on either side of the double bond have different substituents (a phenyl group and a hydrogen atom). Since the rotation around a double bond is restricted, the two different substituents cannot freely interchange their positions. Therefore, this compound exhibits geometrical isomerism.
b) 3-Phenyl-1-butene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (a phenyl group and a hydrogen atom). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
c) 2-Phenyl-1-butene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (a phenyl group and a hydrogen atom). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
d) 1,1-Diphenyl-1-propene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (two phenyl groups). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
Conclusion:
Out of the given options, only 1-Phenyl-2-butene exhibits geometrical isomerism. The presence of a different substituent on each carbon atom of the double bond allows for restricted rotation and different spatial arrangements of atoms.
Geometrical isomerism is a type of stereoisomerism where isomers have the same molecular formula but differ in the arrangement of atoms in space due to restricted rotation around a bond. It occurs when there is a double bond or a ring in the molecule and two different groups or atoms are attached to each of the carbon atoms forming the double bond or ring.
Explanation of the given options:
Let's analyze each option to determine if it exhibits geometrical isomerism.
a) 1-Phenyl-2-butene:
In this compound, there is a double bond between the second and third carbon atoms. The carbon atoms on either side of the double bond have different substituents (a phenyl group and a hydrogen atom). Since the rotation around a double bond is restricted, the two different substituents cannot freely interchange their positions. Therefore, this compound exhibits geometrical isomerism.
b) 3-Phenyl-1-butene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (a phenyl group and a hydrogen atom). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
c) 2-Phenyl-1-butene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (a phenyl group and a hydrogen atom). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
d) 1,1-Diphenyl-1-propene:
In this compound, there is a double bond between the first and second carbon atoms. The carbon atoms on either side of the double bond have the same substituents (two phenyl groups). Since the substituents are the same, there is no possibility of geometrical isomerism in this compound.
Conclusion:
Out of the given options, only 1-Phenyl-2-butene exhibits geometrical isomerism. The presence of a different substituent on each carbon atom of the double bond allows for restricted rotation and different spatial arrangements of atoms.
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Which of the following compounds will exhibit geometrical isomerism ?a...
Option d is correct answer
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Which of the following compounds will exhibit geometrical isomerism ?a)1-Phenyl-2-buteneb)3-Phenyl-1-butenec)2-Phenyl-1-butened)1,1-Diphenyl-1-propeneCorrect answer is option 'A'. Can you explain this answer?
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Which of the following compounds will exhibit geometrical isomerism ?a)1-Phenyl-2-buteneb)3-Phenyl-1-butenec)2-Phenyl-1-butened)1,1-Diphenyl-1-propeneCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following compounds will exhibit geometrical isomerism ?a)1-Phenyl-2-buteneb)3-Phenyl-1-butenec)2-Phenyl-1-butened)1,1-Diphenyl-1-propeneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following compounds will exhibit geometrical isomerism ?a)1-Phenyl-2-buteneb)3-Phenyl-1-butenec)2-Phenyl-1-butened)1,1-Diphenyl-1-propeneCorrect answer is option 'A'. Can you explain this answer?.
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