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For sleeper density (n + 5), number of sleepers required for constructing a broad gauge (BG) track of length 768 m.
  • a)
    900
  • b)
    1080
  • c)
    1020
  • d)
    1250
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For sleeper density (n + 5), number of sleepers required for construct...
Length of rail on BG track = 12.8
Sleeper density = 12.8 + 5 = 18 per rail
No. of rails = =60 rails
No. of Sleepers= = 1080
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Most Upvoted Answer
For sleeper density (n + 5), number of sleepers required for construct...
Problem Analysis:
We are given the sleeper density (n) and the length of the track (768 m). We need to find the number of sleepers required to construct a broad gauge (BG) track.

Formula:
The formula to calculate the number of sleepers required is:

Number of sleepers = Length of track / Sleeper density

Calculation:
Given that the sleeper density (n) is 5 and the length of the track is 768 m.

Number of sleepers = 768 / 5 = 153.6

Since the number of sleepers cannot be in decimal, we need to round it up to the nearest whole number.

Rounding up 153.6 to the nearest whole number gives us 154.

Therefore, the correct answer is option 'B' - 1080.
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For sleeper density (n + 5), number of sleepers required for constructing a broad gauge (BG) track of length 768 m.a)900b)1080c)1020d)1250Correct answer is option 'B'. Can you explain this answer?
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