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ABCD is an isosceles trapezium , i.e., AD = BC, then
- a)AD = CD
- b)∠A = ∠B
- c)∠A = ∠D
- d)∠C = ∠A
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
ABCD is an isosceles trapezium , i.e., AD = BC, thena)AD = CDb)∠A ...
∵ ABCD is an isosceles trapezium.
∴ AD = BC
Draw AE ⊥ DC and BF ⊥ DC, then, in ∆AED and ∠BFC.
∠AED = ∠BFC = 90°,
AB = BC,
AE = BF (perpendicular distance between two parallel lines)
∴ ∆AEB ≅ ∆BFC (ets congruency)
∴ ∠A = ∠B
∴ AD = BC
Draw AE ⊥ DC and BF ⊥ DC, then, in ∆AED and ∠BFC.
∠AED = ∠BFC = 90°,
AB = BC,
AE = BF (perpendicular distance between two parallel lines)
∴ ∆AEB ≅ ∆BFC (ets congruency)
∴ ∠A = ∠B
Most Upvoted Answer
ABCD is an isosceles trapezium , i.e., AD = BC, thena)AD = CDb)∠A ...
∵ ABCD is an isosceles trapezium.
∴ AD = BC
Draw AE ⊥ DC and BF ⊥ DC, then, in ∆AED and ∠BFC.
∠AED = ∠BFC = 90°,
AB = BC,
AE = BF (perpendicular distance between two parallel lines)
∴ ∆AEB ≅ ∆BFC (ets congruency)
∴ ∠A = ∠B
∴ AD = BC
Draw AE ⊥ DC and BF ⊥ DC, then, in ∆AED and ∠BFC.
∠AED = ∠BFC = 90°,
AB = BC,
AE = BF (perpendicular distance between two parallel lines)
∴ ∆AEB ≅ ∆BFC (ets congruency)
∴ ∠A = ∠B
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Community Answer
ABCD is an isosceles trapezium , i.e., AD = BC, thena)AD = CDb)∠A ...
Option b
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