JEE Exam  >  JEE Questions  >  Electrolysis of dilute aqueous NaCl solution ... Start Learning for Free
Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1)              (2008S)
  • a)
    9.65 × 104 sec
  • b)
    19.3 × 104 sec
  • c)
    28.95 × 104 sec
  • d)
    38.6 × 104 sec
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Electrolysis of dilute aqueous NaCl solution was carriedout by passing...
Give : I = 10 milliamperes ; IF = 96500 C mol–1
t = ? ; Moles of H2 produces = 0.01 mol
From the law of electrolysis, we have
Equivalents of H2 produces = 
Substituting given values, we get
i.e. (b) is the correct answer
View all questions of this test
Explore Courses for JEE exam

Similar JEE Doubts

Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer?
Question Description
Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Electrolysis of dilute aqueous NaCl solution was carriedout by passing 10 milli ampere current. The time required toliberate 0.01 mol of H2 gas at the cathode is (1 Faraday =96500 C mol–1) (2008S)a)9.65 × 104 secb)19.3 × 104 secc)28.95 × 104 secd)38.6 × 104 secCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev