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Six wires of current I1 = 1 A, I2 = 2A, I3 = 3A, I4 = 1A, I5 = 5A and I6 = 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integral 
around the closed path.
around the closed path.
Correct answer is 'm0 weber.m_1'. Can you explain this answer?
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Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4...
∫B.dl=µ0I(total current passing through the closed loop)
Currents outside the loop don’t contribute anything to the loop so I5 can be neglected, Also I4 and I6 are going into the loop.
=>∫B.dl= µ0(I1+I2+I3-I4-I6)
= µ0i wb/m
Currents outside the loop don’t contribute anything to the loop so I5 can be neglected, Also I4 and I6 are going into the loop.
=>∫B.dl= µ0(I1+I2+I3-I4-I6)
= µ0i wb/m
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Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4...
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Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4...
∫B.dl=µ0I(total current passing through the closed loop)
Currents outside the loop don’t contribute anything to the loop so I5 can be neglected, Also I4 and I6 are going into the loop.
=>∫B.dl= µ0(I1+I2+I3-I4-I6)
= µ0i wb/m
Currents outside the loop don’t contribute anything to the loop so I5 can be neglected, Also I4 and I6 are going into the loop.
=>∫B.dl= µ0(I1+I2+I3-I4-I6)
= µ0i wb/m
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Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer?
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Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer?.
Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer?.
Solutions for Six wires of current I1= 1 A, I2= 2A, I3= 3A, I4= 1A, I5= 5A and I6= 4A cut the page perpendicularly at the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integralaround the closed path. Correct answer is 'm0 weber.m_1'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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