x² – 37x + 322 = 0y² – 25y + 156 = 0a)X > Yb)...
Given Quadratic Equations:
- x² - 37x + 322 = 0
- y² - 25y + 156 = 0
Comparing the Equations:
- x² - 37x + 322 = (x - 19)(x - 17)
- y² - 25y + 156 = (y - 12)(y - 13)
Finding the Solutions:
- x = 19 or x = 17
- y = 12 or y = 13
Comparing x and y:
Since x can be either 19 or 17, and y can be either 12 or 13,
we can see that x is always greater than y in both cases.
Therefore, the correct answer is:
X > Y