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If each interior angle of a regular polygon is 140°, then the number of vertices of the polygon is equal to
  • a)
    10
  • b)
    9
  • c)
    8
  • d)
    7
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If each interior angle of a regular polygon is 140°, then the numb...
In a polygon, Exterior angle = 180° – Interior angle
⇒ Exterior angle = 180 – 140 = 40°
Sum of exterior angles = Number of sides × Value of each exterior angle
⇒ 360 = n × 40 [ ∵ Sum of exterior angles of any polygon is 360°]
∴ Number of sides, n = 360/40 = 9
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Most Upvoted Answer
If each interior angle of a regular polygon is 140°, then the numb...
The sum of all angles of a polygon is equal to (n-2)*180, where n is the number of sides. For example, for 3-sided triangle, sum of all angles is (3-2)*180 which is 180, similarly for a quadrilateral, the sum is (4-2)*180 which is 360.
Now for a regular polygon where all the sides and angles are equal, every angle will be of the same value (n-2)*180/n. Here it is given that each angle equals 140. So, equate (n-2)*180/n with 140. Vaue of n will be 9.
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If each interior angle of a regular polygon is 140°, then the number of vertices of the polygon is equal toa)10b)9c)8d)7Correct answer is option 'B'. Can you explain this answer?
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