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A polar plot intersects the unit circle at a point making -45° to the negative real axis then the phase margin of the system is : 
  • a)
    -45°
  • b)
    45°
  • c)
    180°-45°
  • d)
    180°+45°
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A polar plot intersects the unit circle at a point making -45° to ...
Answer: b
Explanation: As the angle is with the negative real axis hence the Phase margin will be 45°.
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A polar plot intersects the unit circle at a point making -45° to ...
Degrees with the positive x-axis.

A polar plot is a way of representing a function in polar coordinates, where the distance from the origin represents the value of the function and the angle represents the input variable. The unit circle is a circle with a radius of 1 centered at the origin.

In this case, the polar plot intersects the unit circle at a point making -45 degrees with the positive x-axis. This means that the distance from the origin is 1 (since the point is on the unit circle) and the angle is -45 degrees. The negative angle indicates that the point is in the fourth quadrant, which is below the x-axis and to the right of the y-axis.

To convert this point to rectangular coordinates, we can use the formulas:

x = r cos(theta)
y = r sin(theta)

where r is the distance from the origin and theta is the angle in radians. To convert -45 degrees to radians, we can multiply by pi/180:

-45 degrees = -45 * pi/180 = -pi/4 radians

Plugging in r = 1 and theta = -pi/4, we get:

x = cos(-pi/4) = sqrt(2)/2
y = sin(-pi/4) = -sqrt(2)/2

So the point on the unit circle corresponding to -45 degrees in polar coordinates is:

(sqrt(2)/2, -sqrt(2)/2) in rectangular coordinates.
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