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Haemophilia, is a recessive X-linked trait in human. A population has affected male in the frequency of 2 individuals per 100 males. The frequency of the homozygous female affected with haemophilia would be _____________×10–4.
    Correct answer is '4'. Can you explain this answer?
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    Haemophilia, is a recessive X-linked trait in human. A population has ...
    Affected allele frequency, q= 0.02. frequency of homozygous female is q2 = (0.02)2 = 0.0004.
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    Haemophilia, is a recessive X-linked trait in human. A population has ...
    To calculate the frequency of homozygous females affected with hemophilia, we need to determine the frequency of carriers (heterozygous females) and then square that frequency.

    The frequency of affected males is given as 2 individuals per 100 males, which can be written as 2/100 or 0.02. This represents the frequency of the recessive allele in males, as the condition is X-linked.

    Since hemophilia is a recessive X-linked trait, females can be either homozygous affected or carriers. Assuming Hardy-Weinberg equilibrium, the frequency of carriers can be calculated as the square root of the frequency of affected males.

    √(0.02) = 0.1414

    Therefore, the frequency of carriers (heterozygous females) is approximately 0.1414.

    To calculate the frequency of homozygous affected females, we square the frequency of carriers:

    0.1414 * 0.1414 = 0.02000396

    Therefore, the frequency of homozygous females affected with hemophilia is approximately 0.020 or 2 individuals per 100 females.
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    Haemophilia, is a recessive X-linked trait in human. A population has affected male in the frequency of 2 individuals per 100 males. The frequency of the homozygous female affected with haemophilia would be _____________×10–4.Correct answer is '4'. Can you explain this answer?
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