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x² – 32x + 247 = 0
y² – 22y + 117 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
x² – 32x + 247 = 0y² – 22y + 117 = 0a)X > Yb)...
x² – 32x + 247 = 0
x = 13, 19
y² – 22y + 117 = 0
y = 13, 9
x = 13, 19
y² – 22y + 117 = 0
y = 13, 9
Most Upvoted Answer
x² – 32x + 247 = 0y² – 22y + 117 = 0a)X > Yb)...
Given Quadratic Equations
- The given equations are:
- x^2 - 32x + 247 = 0
- y^2 - 22y + 117 = 0
Finding the Roots
- To determine the relation between x and y, let's first find the roots of the given quadratic equations.
- For the first equation x^2 - 32x + 247 = 0, the roots are x = 13 and x = 19.
- For the second equation y^2 - 22y + 117 = 0, the roots are y = 9 and y = 13.
Comparing the Roots
- We can see that the roots of the second equation are smaller than the roots of the first equation.
- Therefore, we can say that x ≥ y.
Conclusion
- The correct relation between x and y based on the roots of the given quadratic equations is x ≥ y.
- Hence, the correct answer is option C: X ≥ Y.
- The given equations are:
- x^2 - 32x + 247 = 0
- y^2 - 22y + 117 = 0
Finding the Roots
- To determine the relation between x and y, let's first find the roots of the given quadratic equations.
- For the first equation x^2 - 32x + 247 = 0, the roots are x = 13 and x = 19.
- For the second equation y^2 - 22y + 117 = 0, the roots are y = 9 and y = 13.
Comparing the Roots
- We can see that the roots of the second equation are smaller than the roots of the first equation.
- Therefore, we can say that x ≥ y.
Conclusion
- The correct relation between x and y based on the roots of the given quadratic equations is x ≥ y.
- Hence, the correct answer is option C: X ≥ Y.
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Community Answer
x² – 32x + 247 = 0y² – 22y + 117 = 0a)X > Yb)...
x² – 32x + 247 = 0
x = 13, 19
y² – 22y + 117 = 0
y = 13, 9
x = 13, 19
y² – 22y + 117 = 0
y = 13, 9
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Question Description
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