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There are two bodies X and Y with equal kinetic energy but different masses m and 4m respectively. The ratio of their linear momentum is- A: 1:2 B: 4:1 C: 1:√2 D: 1:4 Correct answer is a can uh explain it?
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Introduction:
In this problem, we are given two bodies X and Y with equal kinetic energy but different masses. We need to find the ratio of their linear momentum.

Given information:
- Body X has mass m.
- Body Y has mass 4m.
- Both bodies have equal kinetic energy.

Key concept:
The kinetic energy of an object is given by the equation: KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity. The linear momentum of an object is given by the equation: p = m * v, where p is the linear momentum, m is the mass, and v is the velocity of the object.

Solution:
Since both bodies have equal kinetic energy, we can equate their kinetic energy equations:

0.5 * m * v1^2 = 0.5 * (4m) * v2^2

Simplifying the equation:

m * v1^2 = 2m * v2^2

Dividing both sides by m:

v1^2 = 2 * v2^2

Taking the square root of both sides:

v1 = √(2) * v2

Now, let's find the ratio of their linear momentum:

p1/p2 = (m * v1)/(4m * v2)

Canceling out the masses:

p1/p2 = v1/(4 * v2)

Substituting the value of v1:

p1/p2 = (√(2) * v2)/(4 * v2)

Simplifying the expression:

p1/p2 = √(2)/4

Therefore, the ratio of their linear momentum is 1:2, which is option A.
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There are two bodies X and Y with equal kinetic energy but different masses m and 4m respectively. The ratio of their linear momentum is- A: 1:2 B: 4:1 C: 1:√2 D: 1:4 Correct answer is a can uh explain it?
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