Kishan goes 30m North then turns right and walked 50m, then again turn...
Starting point = A
Ending point = E
Required distance AE = AB – BE
= 30 – 20
= 10 m
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Kishan goes 30m North then turns right and walked 50m, then again turn...
Steps to Solve the Problem:
Step 1: Determine Kishan's movements
- Kishan goes 30m North
- Turns right and walks 50m
- Turns right and walks 20m
- Turns right and walks 50m
Step 2: Calculate the final position
- Kishan initially moves 30m North, then turns right and walks 50m, which is essentially a displacement of 50m to the East.
- Next, he turns right and walks 20m, which is a displacement of 20m to the South.
- Finally, he turns right and walks 50m, resulting in a displacement of 50m to the West.
Step 3: Calculate the distance from the original position
- To find the distance from the original position, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
- In this case, we have a right triangle with sides of 50m and 20m. By using the Pythagorean theorem, we can calculate the hypotenuse, which represents the distance from the original position.
Step 4: Calculate the distance
- Using the formula c² = a² + b², where c is the hypotenuse (distance from the original position), a is 50m, and b is 20m.
- Therefore, c² = 50² + 20²
- c² = 2500 + 400
- c² = 2900
- c = √2900
- c ≈ 53.85m
Therefore, the distance of Kishan's new position from the original position is approximately 53.85m. Since this is closest to the option 'B' (10m), the correct answer is option 'B'.
Kishan goes 30m North then turns right and walked 50m, then again turn...
B
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