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Two genes, B and C have a map distance is 5 cM. The expected frequency of recombinants  in percentage from the cross of BbCc X bbcc is _______________%.
    Correct answer is '5'. Can you explain this answer?
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    Two genes, B and C have a map distance is 5 cM. The expected frequency...
    Map distance 1cM = 1% recombinants of the progenies. Therefore, the expected recombinants frequency of the two genes is 5%.
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    Two genes, B and C have a map distance is 5 cM. The expected frequency of recombinants in percentage from the cross of BbCc X bbcc is _______________%.Correct answer is '5'. Can you explain this answer?
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    Two genes, B and C have a map distance is 5 cM. The expected frequency of recombinants in percentage from the cross of BbCc X bbcc is _______________%.Correct answer is '5'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Two genes, B and C have a map distance is 5 cM. The expected frequency of recombinants in percentage from the cross of BbCc X bbcc is _______________%.Correct answer is '5'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two genes, B and C have a map distance is 5 cM. The expected frequency of recombinants in percentage from the cross of BbCc X bbcc is _______________%.Correct answer is '5'. Can you explain this answer?.
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